Clever Mathematician!

4000 + 2000 = 0 “`

Does this equation confuses you

Long ago, a clever mathematician used to cheat people.Once he borrowed $ 4000/- from a rich man. After a fewdays, he borrowed $ 2000/- from the same man. Manydays passed, the mathematician did not return themoney to the rich man. The rich man went to the mathematician and asked to return the money. But to his great surprise, the mathematician replied that there is no need to pay the debt.

“See here, friend” said the mathematician ” the sum of4000 and 2000 is equal to zero, so I do not have anybalance to pay”.

The rich man took the matter to the court. When thejudge came to know this, he was astonished. He askedthe mathematician to prove that sum of 4000 and 2000 is zero, and not 6000.

The Clever mathematician agreed. He said:

let a = 4000, b = 2000 and c = 6000

a + b = c

Multiply both sides by a + b

(a + b) (a + b) = c (a + b)

a*a + ab + ba + b*b = ca + cb

a*a + ab – ca = cb – b*b – ba

a( a + b -c) = -b(b + a – c)

so a = – b

a + b = 0

Hence by putting the values of “a” and “b” as 4000 and2000 respectively, their sum is zero, so themathematiciansaw no need to pay any money to the rich man.

The above calculation has no doubt surprised you as it did the judge

___________

I know the answer very well … it’s not correct … anyone who can point out the mistake … it’s so easy .. believe me

Wassalam

Comments (8)

RaY-ZoRAugust 19th, 2005 at 5:54 am

Nice one :D .

If a + b = c, and c -s a real number, then according to logic,

a + b cannot equal zero :P . Also, in logical operations, a*b is not the same as b*a, and hence the last step is incorrect. Even mathematically evaluating the last step does not result in a = -b ;) .

شعیب صفدرAugust 19th, 2005 at 11:58 am

interesting……………

Green HeadAugust 19th, 2005 at 9:31 pm

I agree with Ray-zor. He is actually talking about boolean algebra.

dukhtar az PakistanAugust 20th, 2005 at 2:47 am

wat about this
a+b = c
a+b+b= b+c
a+a+2b = a+b+c
2a+2b-2c= a+b+c-2c
2(a+b-c)= a+b-c
2= a+b-c/(a+b-c)
2=1

Dinky MindAugust 21st, 2005 at 11:31 am

yeh lo…post perhnay ki hadd tak to bohat achi hay, magar jab time aaya mistake point out kernay ka to behen….tumhain to pata hay meri math kaisee hay…

*runs away before she fires a question at me*

lol

essjeeAugust 21st, 2005 at 4:21 pm

my dear u have shifted to blogger coments:) am highly oblged..and very happy thanks… atleast i acn coment with ease now..and no more or bahanay :D

mujhay maths ati hoti to doctor banteee???

Harris - حارثAugust 23rd, 2005 at 2:49 am

illegal use of commutative property of addition over multiplication. and DIstributive property of multiplication over addition.

AsmaNovember 10th, 2005 at 4:56 pm

Saadat is right. There is a violation of the division by zero rule in the third last step.

In mathematics, you can’t divide any thing by zero. Or else, not only you, but eveyone reading your work will get screwed. Hehe.
Shuaib | 08.27.05 – 12:32 am | #

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hmmmmmmmmm……….yaar do let me know wats the answere of this
Naqi | Homepage | 08.26.05 – 1:58 pm | #

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Thats pretty amazing. I am not interested.
:P
uXuf | Homepage | 08.26.05 – 4:00 am | #

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Saadat is right … it was so easy … nahiii :O

zenia, umem … u ppl are great

hirdu .. ya ya sure
Asma | Homepage | 08.22.05 – 2:01 am | #

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Nah.

a + b = c
Therefore, a + b – c = 0
In the third last step, the mathematician divided the whole equation with (a + b – c) to get a = -b, i.e., he divided the whole equation by 0.

And according to Mathematics, anything divided by 0 is undefined. So you can’t do that.

*yawns*
Saadat | 08.21.05 – 10:46 pm | #

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Will you then kindly lend me 4000/- this month and rest 2000 next month I shall return by the same math-e-mat-ics !!
hirdu | Homepage | 08.21.05 – 8:37 pm | #

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hahhaha…nice answer by zee.

I have forgotten math, as I studied it 2 years ago.
Dinky Mind | Homepage | 08.21.05 – 12:38 pm | #

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i am on holydayzzz so not math
zenia | 08.21.05 – 9:39 am | #

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